SOLUTIONS IMPROVEMENTS/CLARIFICATIONS/EXTENSIONS
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PAGE NUMBERS ARE PDF PAGES, NOT PAGES AT BOTTOM OF PAGES.

p. 15, 2.11):  For clarity, replace all Dt by Dt, as t is the integration variable.  
Also add to line 4 of part (b) at the end of the sentence:  That way, because
T is the largest that t can ever be for any value of t, Dt = T/Nint,max.   
Also, although the plots are approximately correct, a rerun showed 
a slightly, though insignificantly different appearance in the ratcheting.  9/11/2000

p. 129, 4.12):  Taking the solution one step further, we note that the 
total amplitude at W1 is pA/(2p) = A/2 [overbars on As] where the 1/(2p)
scaling arises from the inverse FT definition, which indeed when combined 
with the negative frequency term does give fc(t) = Acos(W1t + q).      5/12/2000

p. 263. 5.60), line 3.  No error here, but to avoid having to refer to
the evenness of dc for verifying the RHS, change W1 - W2 to W2 - W1.
Technically, we must use the evenness of  dcon line 9.               5/11/2000

p. 295, 6.16), end of text.  Note that there will be replications at -0.4p as well
as +0.4p.  An interesting further question would be if the center modulo occurred
at 0.7Fs.  Then the answer would be -0.3Fs from the positive-frequency
replication (and +0.3Fs from the negative-frequency replication).    12/7/2000

pp. 399-402, 6.68):  One might be concerned about the fact that the left or
right semicircles extend outside the mutual ROC (vertical strip) of the two factors
of the integrand. We may use analytic continuation of the undefined function, for the only
place we care about is the vertical contour, where the original function and its
analytic continuation are identical.  Both factors making up the integrand (the
one defined original and the analytic continuation of the other) are zero;
thus,
the integral we want (that along the vertical portion) is equal to the integral around
the entire D-shaped (or backwards-D-shaped) contour--namely, 2pi*j*sum of
residues of the poles enclosed by the closed contour. One may take limiting
operations to provide a more rigorous argument along these lines.        12/7/2004